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Author Topic: Ajax Checkout partialy working  (Read 1289 times)
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steve_s
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« on: February 22, 2009, 06:02:15 AM »

Hi im just installed on an rc2a with some other mods added, layout etc,
1 When i sign up it creates account but doesnt forward to next step.
2 When i log in, it show my cart, but still stays on login part
3 when i select shipping and payment i get no place order button

here is url for you to check it out http://info-contributions.net84.net/

1 alteration would be purchase without account on sign up too if that mod is installed

Thanks
Steve
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Alex
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« Reply #1 on: February 23, 2009, 06:36:40 AM »

Hello,

The ajax requests at our store are working OK, however, for some reason, each reply is finished with
the following code:

Code:
<!-- www.000webhost.com Analytics Code -->
<script type="text/javascript" src="http://analytics.hosting24.com/count.php"></script>
<noscript><a href="http://www.hosting24.com/"><img src="http://analytics.hosting24.com/count.php" alt
="web hosting" /></a></noscript>
<!-- End Of Code -->

Please remove it from ajax responces, and it will work fine I think, as this for some reason makes parser wrongly parse the reply.
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steve_s
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« Reply #2 on: February 23, 2009, 02:15:54 PM »

Thanks i will try it out,

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steve_s
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« Reply #3 on: February 25, 2009, 01:58:30 PM »

Sorry to be a pain but i couldnt find how to remove that google code seems host is injecting it.

so i set up a local server im using
HTTP Server:     Apache/2.2.11 (Win32) PHP/5.2.8
PHP Version:    5.2.8 (Zend: 2.2.0)

but i get
parse error, expecting `T_FUNCTION' in D:\Program Files\EasyPHP 3.0\www\store\ajax\classes\ajaxManagerTest.class.php on line 480

and on the top of the page i see this
javascript_validation(); ?>

Steve
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steve_s
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« Reply #4 on: March 15, 2009, 04:02:38 PM »

Sorry to be a pain but i couldnt find how to remove that google code seems host is injecting it.

so i set up a local server im using
HTTP Server:     Apache/2.2.11 (Win32) PHP/5.2.8
PHP Version:    5.2.8 (Zend: 2.2.0)

but i get
parse error, expecting `T_FUNCTION' in D:\Program Files\EasyPHP 3.0\www\store\ajax\classes\ajaxManagerTest.class.php on line 480

and on the top of the page i see this
javascript_validation(); ?>

Steve

ok this was due to php 5 needing <?php and wont work with <?
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